(i) With only switch S 1 closed what is the charge on the 3 μ F capacitor in steady state?
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Ans.
(i)
Sol. At steady state
Resistance behave as conducting wire
Charge on capacitor = 12 × 3= 36 μ C
(ii)
Sol. When all switch are closed in steady state circuit will be
Kirchoff law ⇒ 10i + 20 + 20 i – 12 = 0
i = 
Power supplied by battery of 20 V = – 20 × i
= – 20 × 
= 
watt
(iii)
Sol. V A – V B = – 10i + 12
= – 10 
+ 12
V A – V B = 
volt
∴ Charge on 2 μ f
= 
= 
μ C
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